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Hybridisation of the following

Answer»

zation is given by the following FORMULA:H=12(V+X−C+A)H=12(V+X−C+A)Where:VV = number of valence electrons in central atomXX = number of monovalent ATOMS around the central atomCC = positive charge on cationAA = negative charge on anionH=4→sp3,2→sp,3→sp2...H=4→spX3,2→sp,3→spX2...e.g.: in NH3NHX3, the hybridization of NNatom is:H=12(5+3−0+0)=4→sp3⭐⭐⭐⭐⭐ MARK ME BRAINLIST⭐⭐⭐⭐⭐



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