1.

Htaluate YourselfA Compound on analysis gave thelowingpercentage composition24.47%, H=4.07%, 0-71.65%termine the empirical formula of thempoundle​

Answer»

Explanation:

step 1

Divide the GIVEN percentages of atoms with their molecular masses

H---4.07/1 =4.07

C---24.27/12 =2.02

Cl--71.65/35.5=2.01

step 2

divide all VALUES with the lowest value obtained.

H---4.07/2.01=2

C---2.02/2.01=1

Cl---2.01/2.01=1

therefore the empirical FORMULA is

CH

2

Cl

WEIGHT OF EMPIRICAL FORMULA=12+2+35.5=49.5

Given molecular weight =98.96 which is double of empirical weight .therefore molecular formula is C

2

H

4

Cl

2



Discussion

No Comment Found