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Htaluate YourselfA Compound on analysis gave thelowingpercentage composition24.47%, H=4.07%, 0-71.65%termine the empirical formula of thempoundle |
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Answer» Explanation: step 1 Divide the GIVEN percentages of atoms with their molecular masses H---4.07/1 =4.07 C---24.27/12 =2.02 Cl--71.65/35.5=2.01 step 2 divide all VALUES with the lowest value obtained. H---4.07/2.01=2 C---2.02/2.01=1 Cl---2.01/2.01=1 therefore the empirical FORMULA is CH 2
Cl WEIGHT OF EMPIRICAL FORMULA=12+2+35.5=49.5 Given molecular weight =98.96 which is double of empirical weight .therefore molecular formula is C 2
H 4
Cl 2
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