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how would the pressure (exerted by a force on an area) change if -thrust is doubled keeping the area contact |
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Answer» LET PRESSURE be p and. new pressure be. p' thrust be. F Now P=F/A P'=2F/A. (new PRESSURE = 2×thrust/ area) P'=2P. (new PRESSURE= 2×pressure) THEREFORE PRESSURE WILL ALSO BE DOUBLED |
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