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How to write reduction and oxidation half reaction...plx... explain kar k dou with example...i will mark that person as brainliest....plzz ... urgent hai.... |
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Answer» You can write a REDOX reaction as two half-reactions, one showing the reduction process, and one showing the oxidation process. FE3+ is GAINING an electron to become Fe2+. Iron is therefore being reduced and tin is the reducing agent (causing iron to be reduced). The reduction half-reaction is: Fe3+(AQ) + e−→Fe2+(aq) Sn2+ is losing two electrons to become Sn4+. Tin is therefore being oxidised and iron is the oxidising agent (causing tin to be oxidised). The oxidation half-reaction is: Sn2+(aq)→Sn4+(aq) + 2e−Explanation:plzz mark me as a brainlist |
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