How to solve it can anyone tell me plz

1.	How to solve it can anyone tell me plz
Answer» since two resistance are parallel 1/Rp= (1/3 +1/6 ) Rp= 2ohm Now other three are in paralllel 1/Rp = 1/3 +1/6+1/2 1/Rp= 6/6ohm=1OHM Rp= 1ohm Now above two are in parallel so Rs (EQ)= 2+1=3ohm total voltage = 12v i = V/R=12/3=4A since the 3 ohm and 6ohm are in paralllel so using current DIVISION rule current in 3ohm is 4/3a and In 6 ohm is 8/3a Now 4/3A is divided in 3 resistor so current divided in ratio 3:2:1 so current in Ammeter is = 4A in downward Now current in Ammeter DUR to 6ohm resistor= 2A upward so reading of Ammeter is = 4 - 2 = 2A upward .

Answer»

since two resistance are parallel

1/Rp= (1/3 +1/6 )

Rp= 2ohm

Now other three are in paralllel

1/Rp = 1/3 +1/6+1/2

1/Rp= 6/6ohm=1OHM

Rp= 1ohm

Now above two are in parallel so

Rs (EQ)= 2+1=3ohm

total voltage = 12v

i = V/R=12/3=4A

since the 3 ohm and 6ohm are in paralllel so using current DIVISION rule

current in 3ohm is 4/3a and In 6 ohm is 8/3a

Now 4/3A is divided in 3 resistor so

current divided in ratio 3:2:1

so current in Ammeter is = 4A in downward

Now

current in Ammeter DUR to 6ohm resistor= 2A upward

so reading of Ammeter is = 4 - 2 = 2A upward .

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