How to proove a^3+b^3+c^3-3abc =1÷2(a+b+c){(a-b)^2+(b-c)^2+(c-a)^2}

1.	How to proove a^3+b^3+c^3-3abc =1÷2(a+b+c){(a-b)^2+(b-c)^2+(c-a)^2}
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