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Answer» Hello dear,
Locating √10 on a number line :
Here, 10 = 3² + 1
.............[ See the attached image (II) √10 ]..........
So, draw a right angled OAB, in which OA = 3 units and AB = 1 unit and angle OAB = 90° .
By using Pythagoras theorem, we get
Taking OB = √10 as RADIUS and point O as centre, draw an arc which meets the number line at point P on the positive side of it. The point P represents √10 on the number line.
Hope it HELPS.
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