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| 1. |
How to identify that the element is formed by single, double or triple covalent bond? |
| Answer» Cos²A+(1+sin²A) /CosA(1+sinA)Cos²A+1+Sin²A+2sinA/CosA(1+SinA)1+1+2sinA\\CosA(1+sinA)2+2sinA\\CosA(1+sinA)2(1+SinA)\\CosA(1+SinA)2\\CosA= 2SecA | |