1.

HOW TO FIND THE GOLD NUMBER OF AN ELECTROLYTE?

Answer»

Hardy schulze rule

“Greater is the valency of coagulating ion added, the greater is its power to cause precipitation ”. In the COAGULATION of a negative colloidal solution the coagulating power is as :

All^3++ > Ba^++ > Na^+

In the coagulation of a positive colloidal solution the following power is as :

[ Fe(CN)6]^4- , Po4^3-, SO4^2- , Cl^-

Protection of colloids:

Lyophobic colloidal solutions  are coagulated on addition of electrolytes while lyophillic colloidal solutions are not coagulated by electrolyte . If small amount of lyophillic colloidal solution is present along with a lyophobic colloidal solution, the addition of a small amount of electrolyte does not coagulate either of them. It means  presence of lyophillic colloidal solution prevents a lyophobic colloidal solution from coagulation. This phenomenon is known as protection & the lyophillic colloid used for this purpose is known as protective colloid.

When a lyophillic colloid is added to a lyophobic colloidal solution, the particles of lyophobic colloidal solution adsorbs the particles of lyophillic colloid around them & behaves like lyophillic colloidal solution. This prevent them from coagulation.

Gold Number:

” The Gold number is defined as the number of milligrams of the protective colloid in dry state which when added to 10 ml of a colloidal solution of gold, prevents the gold solution from coagulation on addition of 1 ml of 10%  NaCl solution.”

Gold number of different lyophillic colloids are different. Lesser is the gold number greater is the protective power.

Question : The coagulation of 100 ml of a colloidal solution of gold is completely prevented by adding 0.25 gm of starch to it before adding 10 ml of 10% NaCl solution. Find out the gold number of starch ?

solution:

100 ml gold solution requires = 0.25 gm starch ( i.e 250 mg starch)

10 ml gold solution requires = 250 × 10 / 100 = 25 mg

10ml of 10 % NaCl solution is added to 100 ml gold solution. Thus 1 ml of 10% NaCl solution been added to 10 ml solution of gold.

Question: The coagulation of 10 ml of a colloidal solution of gold  can be completely STOPPED by the  addition of  0.025 gms of starch before the addition of  1 ml of 10% NaCl solution. What  is  the gold number ?

solution:

Coagulation of 10 ml of colloidal solution of gold can be stopped by the addition of

1 ml of 10% NaCl = number of milligrams of starch

= 0.025 gm =  0.025 × 1000 mg = 25 mg.

HOPE IT HELPS...
PLEASE PLEASE MARK AS BRAINLIEST.



Discussion

No Comment Found