Solution:22½° lies in the first quadrant.Therefore, TAN 22½° is positive.For all positive VALUES of the ANGLE A we KNOW that, tan A2 = √1−cosA1+cosAtan 22½° = √1−cos45°1+cos45°tan 22½° = √1−1√21+1√2, [Since we know that cos 45° = 1√2]tan 22½° = √√2−1√2+1tan 22½° = √√2−1√2+1⋅√2−1√2−1tan 22½° = √(√2−1)22−1tan 22½° = √2 - 1Therefore, tan 22½° = √2 - 1
Your experience on this site will be improved by allowing cookies. Read Cookie Policy