How much would it cost to paint the walls of a room10 m long, 8 m wide

1.	How much would it cost to paint the walls of a room10 m long, 8 m wide and 4 m high, if painting 1 m²costs 6.50?
Answer» Before, finding the answer. LET's find out we can find the answer. In this question, we are asked to find the COST of painting the walls of a ROOM. So, to find that, we must find the Lateral Surface Area of the Cuboid. To find the Lateral Surface Area, we must use the formula of : $\boxed{\sf Lateral \: Surface \: Area \: of \:Cuboid = <klux>2</klux> h (l+ b)}$ After finding the Lateral Surface Area, we must multiply the cost of painting with the Lateral Surface Area. _______________________________ Given : Length = 10 m Breadth = 8 m Height = 4 m Cost for Painting = Rs. 6.50 To find : cost to paint Solution : Lateral Surface Area = 2 h (l+ b) = 2 × 4 × (10 + 8) = 2 × 4 × (18) = 2 × 72 = 144 cm² Cost for Painting = Cost of Painting × Lateral Surface Area = 6.50 × 144 = 936 Therefore, the Cost of Painting the walls of the room is Rs. 936.

How much would it cost to paint the walls of a room10 m long, 8 m wide and 4 m high, if painting 1 m²costs 6.50?

Answer»

Before, finding the answer. LET's find out we can find the answer.

In this question, we are asked to find the COST of painting the walls of a ROOM.
So, to find that, we must find the Lateral Surface Area of the Cuboid. To find the Lateral Surface Area, we must use the formula of :

$\boxed{\sf Lateral \: Surface \: Area \: of \:Cuboid = <klux>2</klux> h (l+ b)}$

After finding the Lateral Surface Area, we must multiply the cost of painting with the Lateral Surface Area.

_______________________________

Given :

To find :

Solution :

Lateral Surface Area = 2 h (l+ b)

= 2 × 4 × (10 + 8)

= 2 × 4 × (18)

= 2 × 72

= 144 cm²

Cost for Painting = Cost of Painting × Lateral Surface Area

= 6.50 × 144

= 936

Therefore, the Cost of Painting the walls of the room is Rs. 936.