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How much work will be done in increasing the diameter of a soap bubble from 2cm to 5cm? Surface tension solution is `3.0xx10^(-2)N//m.` |
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Answer» Correct Answer - A::C::D Soap bubble has two surface, Hence, `W=T Delta A (T=(Delta W)/(Delta A))` Here,` DeltaA= 2[4 pi {(2.5xx10^(-2))^(2)-(1.0xx10^(-2))^(2)}]` `=1.32xx10^(-2)m^(2)` `:. W=(3.0xx10^(-2))(1.32xx10^(-2))J` `=3.96xx10^(4) J`. |
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