1.

How much will be the coefficient of friction for moving a body of mass 80 kg by a force of 40 kg on a horizontal surface?​

Answer»

EXPLANATION:

Let a be the acceleration of the box.

The EQUATION of motion of the box, ma=F−f (as friction force always OPPOSITE to APPLIED force)

or 40a=80−60

or a=20/40=0.5m/s

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