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How much will be the coefficient of friction for moving a body of mass 80 kg by a force of 40 kg on a horizontal surface? |
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Answer» Let a be the acceleration of the box. The EQUATION of motion of the box, ma=F−f (as friction force always OPPOSITE to APPLIED force) or 40a=80−60 or a=20/40=0.5m/s 2 |
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