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How much pure alcohol should added to 400 ml of strength 15% to make its strength 32%? plzz answer |
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Answer»
Solution:- Let the REQUIRED number of milliliters of ALCOHOLS be x ml. Given 15 % of 400 ml should be added with 100 % of PURE alcohol. Hence 400(15 %) + x(100 %) = (400+x) (32 %) ⇒ 400 × 15/100 + x = (400 + x) × (32/100) ⇒ 60 + x = 128 + (8x/25) ⇒ x - 8x/25 = 128 - 60 ⇒ 17x/25 = 68 ⇒ x = (68 × 25)/17 ⇒ x = 1700/17 x = 100 ml Answer Plz follow me Plz mark as brainlist answer |
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