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How much metal is required to make a 20 metre long pipe, if its inner and outer diameter are 6 metre and 8 metre respectively.

Answer»

\underline {\pink{ Dimensions \: of \: a \: metal \:pipe : }}

Length \:of \:the \: pipe (h) = 20 \:m

Inner \: Diameter (d) = 6 \:m

Inner \: radius (r) = \frac{d}{2}

= \frac{6}{2}

= 3 \: m

Outer \: Diameter (D) = 8\:m

Outer \: radius (R) = \frac{D}{2}

= \frac{8}{2}

= 4 \: m

\red{ Metal \: required \: to \: make \:the \:pipe }

= \pi h ( R^{2} - r^{2} )

= \pi h ( R + r )( R - r )

= \frac{22}{7} \times 20 \times ( 4 + 3 )( 4 - 3 )

= \frac{22}{7} \times 20 \times 7 \times  1

= 22\times 20

= 440 \: m^{3}

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