How much marble of 96.5% purity would be required to prepare 100 litres of carbon dioxide at STP when marble is acted upon by dil HCL?

How much marble of 96.5% purity would be required to prepare 100 litre

1.	How much marble of 96.5% purity would be required to prepare 100 litres of carbon dioxide at STP when marble is acted upon by dil HCL?
Answer» ONG>Answer: 22.4 L of C02 at N.T.P. is obtained from CAC03 = 100g 100 L of C02 at N.T.P. will be obtained from CaC03 100 = —X 100 = 446.4 G 22.4 446.4 x 100 mpure marble required = 462.6 g• 96.5 0 63.