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How much heat energy is necessary to raise the temperature of 5 kg of water from 20^@C to 100^@C. |
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Answer» Solution :Given : m=5 kg, c=1 KCAL/`kg^@C` Change in temperature `(DeltaT)`=100-20 =`80^@C` To Find : Heat energy needed to raise the temperature Solution :Energy to be SUPPLIED to WATER = energy gained by water = mass of water X specific heat of water change in temperature of water = `mxxcxxDeltaT` = 5 x 1 x 80 = 400 kcal HENCE, the heat energy necessary to raise the temperature of water is 400 kcal. |
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