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How much energy is transferred when 1 gm of boiling water at 100°C cools to water at 0°C ? |
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Answer» Stage 1 → Heat releases from water vapour at 100°C When converts into water at 100°C = Latent heat of vapourization = 540 cal (Q1) Stage 2 → Heat energy releases from water at 100°C When converts into water at 0°C Q2 = mSΔT, Here ΔT = 100°C – 0°C = 100°C (∵ m = 1 gm; S = 1 Cal/gm°C.) = 1 ×1 ×100 = 100 Cal. Total energy releases ⇒ Q1 + Q2 ⇒ 540 + 100 ⇒ 640 Cal. |
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