1.

How much energy is transferred when 1 gm of boiling water at 100°C cools to water at 0°C ?

Answer»

Stage 1 → Heat releases from water vapour at 100°C

When converts into water at 100°C = Latent heat of vapourization

= 540 cal (Q1)

Stage 2 → Heat energy releases from water at 100°C

When converts into water at 0°C

Q2 = mSΔT, Here ΔT = 100°C – 0°C = 100°C 

(  m = 1 gm; S = 1 Cal/gm°C.)

= 1 ×1 ×100 = 100 Cal.

Total energy releases ⇒ Q1 + Q2 ⇒ 540 + 100 ⇒ 640 Cal.



Discussion

No Comment Found

Related InterviewSolutions