How much energy is released or absorbed when 1 gm of steam at 100°C t

1.	How much energy is released or absorbed when 1 gm of steam at 100°C turns to ice at 0°C ?
Answer» Stage – 1 : Heat energy releases from water vapour at 100°C When converts into water at 100°C Q₁ = Latent heat of vapourization (L) = 540 Cal. Stage – 2 : Heat energy releases from water at 100°C. When converts into water at 0°C. Q₂ = mSΔT. Here m = 1 gm; S = 1 Cal/gm°C ΔT = 100°C – 0°C ⇒ 100°C = 1.1.100 = 100 Cal Stage – 3 : Heat energy releases from water (0°C) When converts into ice (0°C) Q₃ = Latent heat of fusion (L_fusion) = 80 Cal. Total energy releases = Q₁ + Q₂ + Q₃= 540 + 100 + 80 = 720 Cal.

How much energy is released or absorbed when 1 gm of steam at 100°C turns to ice at 0°C ?

Answer»

Stage – 1 : Heat energy releases from water vapour at 100°C

When converts into water at 100°C

Q₁ = Latent heat of vapourization (L) = 540 Cal.

Stage – 2 : Heat energy releases from water at 100°C.

When converts into water at 0°C.

Q₂ = mSΔT. Here m = 1 gm; S = 1 Cal/gm°C

ΔT = 100°C – 0°C ⇒ 100°C = 1.1.100 = 100 Cal

Stage – 3 : Heat energy releases from water (0°C)

When converts into ice (0°C)

Q₃ = Latent heat of fusion (L_fusion) = 80 Cal.

Total energy releases = Q₁ + Q₂ + Q₃= 540 + 100 + 80 = 720 Cal.

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