How much electricity in terms of Faraday is required to carry out the

1.	How much electricity in terms of Faraday is required to carry out the reduction of one mole of PbO2
Answer» The cell reaction that takes place in a lead storage battery are: Pb + PbO₂ + 4H⁺ + SO₄^-2 → 2PbSO₄ + 2H₂O In this reaction Pb shows an oxidation state of +4. It gets reduced to PbSO₄ which shows an oxidation state of +2. In this reaction, 2 electrons are necessary for the reduction of PbO₂. Pb⁴⁺ + 2e^- -----------> Pb²⁺ Therefore, as 2 electrons were needed for the reduction, the Faraday’s law of electrolysis stated that: The reduction of 1 mole of PbO₂ required 2F electricity.

How much electricity in terms of Faraday is required to carry out the reduction of one mole of PbO2

Answer»

The cell reaction that takes place in a lead storage battery are:

Pb + PbO₂ + 4H⁺ + SO₄^-2 → 2PbSO₄ + 2H₂O

In this reaction Pb shows an oxidation state of +4. It gets reduced to PbSO₄ which shows an oxidation state of +2.

In this reaction, 2 electrons are necessary for the reduction of PbO₂.

Pb⁴⁺ + 2e^- -----------> Pb²⁺

Therefore, as 2 electrons were needed for the reduction, the Faraday’s law of electrolysis stated that:

The reduction of 1 mole of PbO₂ required 2F electricity.

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