1.

How much cao will be produced by decomposition of 5gm caco3 ?

Answer»

Answer:

2.8g (or 0.05 moles)

EXPLANATION:

\\\tt  CaCO_{3} \rightleftharpoons  CaO + CO_{2}

Molar MASS of \\\tt CaCO_{3} = {40 +12 + 3(16)}g/mol =  100g/mol

Molar mass of CaO = (40 + 16)g/mol = 56g/mol

For 1 mole of \\\tt CaCO_{3} 1 mole of CaO will be PRODUCED.

Number of moles of \\\tt CaCO_{3} in 5g = \\\tt \dfrac{5}{100} mol = 0.05mol

Therfore 0.05 mol of CaO will be produced whose mass will be \\\tt 0.05 \times 56 g = 2.8g



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