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How manyspherical bullets can be made out of a solid cube of lead whose edge measures44 cm, each being 4 cm in diameter. |
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Answer» Given that,lost of spherical lead shots made out a soild cube of lead `therefore` Number of spherical shots `= ("Volumeof a solid cube of lead")/("Volume of a spherical lead shot") ` Given that, diameter of a spherical lead shot i.e, sphere = 4 cm `rArr" ""Radius of a spheical lead shot "(r)=(4)/(2)` `r = 2cm " "[therefore "diameter " = 2xx "radius"]` So Volume of a spherical lead shot i..e, sphere `" "= (4)/(3) pi r^(3)` `" "(4)/(3) xx (22)/(7) xx (2)^(3) ` `" "= (4 xx 22 xx 8)/(21) cm^(3)` Now, sine edge of a solid cube (a) = 44 cm so, volume of a soild `= (a)^(3) = (44)^(3) = 44 xx 44 cm^(3)` From Eq. (i) Number of spherical lead shots `= (44 xx 44 xx 44)/(4 xx 22 xx 8) xx 21` `" " = 11 xx 21 xx 11 = 121 xx 21` `" " =2541` Hence, the required number of spherical lead shots is 2541. |
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