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How many unpaired electrons are present in the ground state of Fe3+(z = 26 ), Mn2+ (25) and Neon (z= 10). |
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Answer» Explanation: For determining the unpaired electrons remember that you need to remove the electrons from the HIGHEST 'n' (principal quantum number ) so here we go 1. Fe (z=26) Fe = 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d⁶ REMOVING 3 electrons from 4s and 3d because 4s can't remove more than 2 so now FE3+ = 1s² 2s² 2p⁶ 3s² 3p⁶ 4s⁰ 3d⁵ as in d orbital only 10 electrons can be accommodated let's see
Out of those 10 5 will be of one spin and 5 of opposite spin So 5 unpaired electrons Mn (z= 25) Mn= 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d⁵ removing 2 electrons from 4s orbital Mn2+ = 1s² 2s² 2p⁶ 3s² 3p⁶ 4s⁰ 3d⁵ here also 5 unpaired Neon =1s² 2s² 2p⁶ no unpaired as it's an inert gas Thank U ☺️ |
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