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How many spherical bullets can be made out of a solid cube of lead whose edge measures 44 cm, each bullet being 4 cm in diameter?

Answer»

Volume of a cube = side3

Volume of a sphere = \(\frac{4}{3}\)πr3 

Given, 

spherical bullets are to be made out of a solid cube of lead whose edge measures 44 cm, each bullet being 4 cm in diameter. 

Let the number of bullets be ‘a’. 

⇒ 443 = a × \(\frac{4}{3}\)× \(\frac{22}{7}\) × 23 

⇒ a = 2541



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