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How many proton in 100g caco3 |
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Answer» Well, calcium CARBONATE, or limestone, has a CHEMICAL formula of C a C O 3 . It has a molar MASS of around 100 g/mol . So, in 10 g of calcium carbonate, there will be 10 g 100 g /mol = 0.1 mol So, there will be 0.1 moles of calcium carbonate in this sample. One mole of molecules is defined by 6.02 ⋅ 10 23 molecules. Therefore, there exist 6.02 ⋅ 10 23 ⋅ 0.1 = 6.02 ⋅ 10 22 molecules of calcium carbonate. C a C O 3 CONSISTS of one calcium atom, one CARBON atom, and three oxygen atoms. A calcium atom has 20 protons, a carbon atom has 6 protons, and one oxygen atom has 8 protons, and so three oxygen atoms would have 8 ⋅ 3 = 24 protons. In total, one molecule of calcium carbonate has 20 + 6 + 24 = 50 protons. But, we have 6.02 ⋅ 10 22 molecules of calcium carbonate. Therefore, in total, we would have 6.02 ⋅ 10 22 ⋅ 50 = 3.01 ⋅ 10 24 protons. |
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