How many particle will be present in 270 gram of glucose calculate the

1.	How many particle will be present in 270 gram of glucose calculate the mole also
Answer» GLUCOSE = C6H12O6 = 72 +12 + 96 = 180 moles = wt/mol.wt = 270/180 = 1.5 moles. 1 MOLE contains 6.023 x 10^23 glucose molecules. therefore 1.5 moles contains 9.0345x10^23 molecules of glucose.

How many particle will be present in 270 gram of glucose calculate the mole also

Answer»

GLUCOSE = C6H12O6 = 72 +12 + 96 = 180

moles = wt/mol.wt = 270/180 = 1.5 moles.

1 MOLE contains 6.023 x 10^23 glucose molecules.

therefore 1.5 moles contains 9.0345x10^23 molecules of glucose.