How many pairs of natural numbers are there such that the difference o

1.	How many pairs of natural numbers are there such that the difference of whose squares is 63?1. 32. 43. 54. 2
Answer» Correct Answer - Option 1 : 3 Given: Difference between the square of two numbers is 63. Calculation: Let the numbers be x and y, where x > y According to question. ⇒ x² - y² = 63 ⇒ (x + y)(x - y) = 63 Factore of 63 are (63, 1), (21, 3) and (9, 7) There will be 3 pairs whose square difference is 63. The numbers will be ⇒ x + y = 63 ⇒ x - y = 1 So, pair one will be x = 32 and y = 31 ⇒ x + y = 9 ⇒ x - y = 7 So, pair one will be x = 8 and y = 1. ∴ Three pairs of natural number whose difference of square is 63.

How many pairs of natural numbers are there such that the difference of whose squares is 63?1. 32. 43. 54. 2

Answer» Correct Answer - Option 1 : 3

Given:

Difference between the square of two numbers is 63.

Calculation:

Let the numbers be x and y, where x > y

According to question.

⇒ x² - y² = 63

⇒ (x + y)(x - y) = 63

Factore of 63 are (63, 1), (21, 3) and (9, 7)

There will be 3 pairs whose square difference is 63.

The numbers will be

⇒ x + y = 63

⇒ x - y = 1

So, pair one will be x = 32 and y = 31

⇒ x + y = 9

⇒ x - y = 7

So, pair one will be x = 8 and y = 1.

∴ Three pairs of natural number whose difference of square is 63.

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