How many oxygen atoms will be present in 88 gram of seo2?

1.	How many oxygen atoms will be present in 88 gram of seo2?
Answer» Molar mass of CO2 = 44g/mol Number of moles of CO2 present in 88g of CO2 = 88g/44g mol-1 = 2 moles 1 mole of CO2 contains 2 moles of Oxygen ATOMS. Hence 2 moles of CO2 contains 4 moles of Oxygen atoms 1 mole of oxygen contains 6.023 X 1023 atoms of oxygen 4 moles of oxygen contains = 4 X 6.023 X 1023 = 24.092 X 1023 = 2.4092 X 1024 atoms of oxygen Therefore 88g of CO2 Contains 2.4092 X 1024 atoms of oxygen

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