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How many numbers of two digits are divisible by 5? ( apply nth term of the AP) |
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Answer» 2 DIGIT smallest no.is10,which is multiple of 5 A1=10 An=95 d=5 An=A+(n-1)d =95=10+(n-1)5 =85=5n-5 =90=5n n=18 there is 18 no.divisible by 5 ,of 2 digit |
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