1.

How many numbers of two digits are divisible by 5? ( apply nth term of the AP)

Answer»

2 DIGIT smallest no.is10,which is multiple of 5

A1=10

An=95

d=5

An=A+(n-1)d

=95=10+(n-1)5

=85=5n-5

=90=5n

n=18

there is 18 no.divisible by 5 ,of 2 digit



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