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How many Na electrons is present in 5.1g NH3 plzz tell correct ....I will be thankful |
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Answer» 14.44 * 10^23 electrons are present in 5.1 g NH3Explanation:17 is the molar mass of NH35.1 /17 gives the NUMBER of MOLES of NH3 in 5.1 grams of it. MULTIPLYING by 8 because in 1 mol NH3 there are 8 electrons. (Refer Lewis dot structure of NH3). Hence in 5.1 g 6.02 * 10^23 times electrons would be present. |
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