How many moles of sodium cyanide (NaCN) would be needed to produce 4.2 moles of sodium sulfate (Na2SO4)? H2SO4 + 2NaCN → 2HCN + Na2SO4 (4 points)

How many moles of sodium cyanide (NaCN) would be needed to produce 4.2

1.	How many moles of sodium cyanide (NaCN) would be needed to produce 4.2 moles of sodium sulfate (Na2SO4)? H2SO4 + 2NaCN → 2HCN + Na2SO4 (4 points)
Answer» H2SO4 + 2NACN → 2HCN + NA2SO4 (4 POINTS)