HOW MANY MOLES OF NITROGEN ARE NEEDED TO PRODUCE 8.2 MOLE OF AMMONIA B

1.	HOW MANY MOLES OF NITROGEN ARE NEEDED TO PRODUCE 8.2 MOLE OF AMMONIA BY THE REACTION WITH HYDROGEN?
Answer» Here is how you crack it up; WRITE a balanced CHEMICAL equation for the reaction N + H ⇄ NH3 since these elements exist as diatomic gases, ∴N2 + H2 ⇄ NH3 now to balance it, make sure the number of atoms on both SIDES of the equation are equal, thus; N2 + 3H2 ⇄ 2NH3. Now to compare the MOLE ratios there is 1mol of N2 which reacted with 3mol of H2 to produce 2mol of NH3 we say, 1mol(N2) : 2mol(NH3) Xmol : 8.2mol , and to do the calculation, 2X = 8.2, = 4.1mol of N2 Hence, 4.1mol of N2 were needed to produce 8.2moles of NH3

HOW MANY MOLES OF NITROGEN ARE NEEDED TO PRODUCE 8.2 MOLE OF AMMONIA BY THE REACTION WITH HYDROGEN?

Answer»

Here is how you crack it up;

WRITE a balanced CHEMICAL equation for the reaction

N + H ⇄ NH3

since these elements exist as diatomic gases,

∴N2 + H2 ⇄ NH3

now to balance it, make sure the number of atoms on both SIDES of the equation are equal, thus;

N2 + 3H2 ⇄ 2NH3. Now to compare the MOLE ratios

there is 1mol of N2 which reacted with 3mol of H2 to produce 2mol of NH3

we say, 1mol(N2) : 2mol(NH3)

Xmol : 8.2mol , and to do the calculation,

2X = 8.2,

= 4.1mol of N2

Hence, 4.1mol of N2 were needed to produce 8.2moles of NH3