How many moles of naoh are present in 27ml of 0.015 M of naoh.explain

1.	How many moles of naoh are present in 27ml of 0.015 M of naoh.explain
Answer» AOH in 27 ML = 40x0.15x27/1000 = 0.162 GM MOL of NaOH = 0.162/40 = 0.00405 mol

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