1.

How many moles of NaOH are present in 27mL of 0.015 M NaOH ?

Answer»

`4.05 xx 10^(-3)`
`4.05 xx 10^(-4)`
`4.05 `
`0.0405 `

Solution :MOLES of `NAOH= (0.015)/(1000) xx 27 ml `
` = 4.05 xx 10^(-4) ` mol


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