How many moles of ferric alum (NH4)2SO4·Fe2(SO4)3·24H2O can be made from the sampleof Fe containing 0.0056 g of it ?[Atomic mass of Fe = 56 u](1) 10–4 mol (2) 0.5 × 10–4 mol(3) 0.33 × 10–4 mol (4) 2 × 10–4 mol

How many moles of ferric alum (NH4)2SO4·Fe2(SO4)3·24H2O can be made

1.	How many moles of ferric alum (NH4)2SO4·Fe2(SO4)3·24H2O can be made from the sampleof Fe containing 0.0056 g of it ?[Atomic mass of Fe = 56 u](1) 10–4 mol (2) 0.5 × 10–4 mol(3) 0.33 × 10–4 mol (4) 2 × 10–4 mol
Answer» 112G of Fe is contained in---->1 mole of ferric alum therefore 5.6 * 10^-3g of Fe will be in ----->(1/112)5.610^-3 =====> 0.5 * 10^-4 mol.of ferric alum. The ANS. is (2) 0.5 * 10^-4 Hope it HELPS.