How many moles of copper are presnet in 148.2g Ca(OH)2

1.	How many moles of copper are presnet in 148.2g Ca(OH)2
Answer» Answer: 2 moles. Logic: no of moles $\\\tt \longrightarrow$ $\\\tt \dfrac{<klux>MASS</klux>\ of\ substance}{molar\ mass}$ STEPS: Mass of $\\\tt Ca(OH)_2$ = Mass of Ca + 2 (Mass of O) + 2(Mass of H) = 40 amu + 32 amu + 2amu = 74 amu. Moles of $\\\tt Ca(OH)_2$ will be $\dfrac{148.2}{74} \\\tt \\\tt = 2.0027$

Answer»