How many moles of co2 will left if 10^21 molecules are removed from 51

1.	How many moles of co2 will left if 10^21 molecules are removed from 513.07mg of co2
Answer» Answer:- 0.01 mole Explanation:- • Molar mass of Carbon (C) = 12g/mol • Molar mass of OXYGEN (O) = 16g/mol • AVOGADRO Number = 6.022×10²³ Hence, molar mass of CO₂ :- = 12 + 16×2 = 12 + 32 = 44g/mol • Given Mass of CO₂ :- = 513.07mg= 0.51307g Number of moles in 0.51307g of CO₂ :- = Given Mass/Molar mass = 0.51307/44 = 0.0116 mole [APPROXIMATELY] Now, from 0.116 moles of CO₂ , 10²¹ molecules are removed. Number of moles in 10²¹ molecules of CO₂ :- = No of molecules/Avogadro Number = 10²¹/[6.022×10²³] = 1/[6.022×10²] = 1/602.2 = 0.0016 mole [approximately] Therefore, number of moles of CO₂ LEFT :- = 0.0116 - 0.0016 = 0.01 mole Thus, 0.01 mole of CO₂ are left.

How many moles of co2 will left if 10^21 molecules are removed from 513.07mg of co2

Answer»

0.01 mole

• Molar mass of Carbon (C) = 12g/mol

• Molar mass of OXYGEN (O) = 16g/mol

• AVOGADRO Number = 6.022×10²³

Hence, molar mass of CO₂ :-

= 12 + 16×2

= 12 + 32

= 44g/mol

• Given Mass of CO₂ :-

= 513.07mg= 0.51307g

Number of moles in 0.51307g of CO₂ :-

= Given Mass/Molar mass

= 0.51307/44

= 0.0116 mole [APPROXIMATELY]

Now, from 0.116 moles of CO₂ , 10²¹ molecules are removed.

Number of moles in 10²¹ molecules

of CO₂ :-

= No of molecules/Avogadro Number

= 10²¹/[6.022×10²³]

= 1/[6.022×10²]

= 1/602.2

= 0.0016 mole [approximately]

Therefore, number of moles of CO₂ LEFT :-

= 0.0116 - 0.0016

= 0.01 mole

Thus, 0.01 mole of CO₂ are left.