1.

How many moles and how many grams of sodium chloride are present in 250 cm3 of a 0.500 m nacl solution?

Answer»

Answer:

Explanation:

Given Molarity = 0.500 M

Volume of the solution = 250 cm³ = 0.250 L

Molarity is defined as the number of moles of SOLUTE present in one Liter of the solution. Mathematically,

Molarity = Number of moles of solute/ Volume of solution (L)

PUTTING NUMERICAL values,

⇒0.5 = Number of moles of solute/0.250

⇒Number of moles of solute = 0.5 x 0.250 = 0. 125 moles

Thus, number of moles of sodium CHLORIDE = 0.125 moles

Mass of sodium chloride = Number of moles x molar mass

                                           = 0.125 x 58.5 G

                                           = 7.1325 g



Discussion

No Comment Found