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How many moles and how many grams of sodium chloride are present in 250 cm3 of a 0.500 m nacl solution? |
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Answer» Answer: Explanation: Given Molarity = 0.500 M Volume of the solution = 250 cm³ = 0.250 L Molarity is defined as the number of moles of SOLUTE present in one Liter of the solution. Mathematically, Molarity = Number of moles of solute/ Volume of solution (L) ⇒0.5 = Number of moles of solute/0.250 ⇒Number of moles of solute = 0.5 x 0.250 = 0. 125 moles Thus, number of moles of sodium CHLORIDE = 0.125 moles Mass of sodium chloride = Number of moles x molar mass = 0.125 x 58.5 G = 7.1325 g |
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