How many moles and how many gram of Nacl are present in 250ml of 0.50M

1.	How many moles and how many gram of Nacl are present in 250ml of 0.50M in a solution
Answer» Bonjour! No. of moles = ? Gram of NACL = ? Molecular weight of NaCl = 58.5 g Volume of solution = 250 ML Molarity = 0.50 M or M/2 $molarity = \frac{<klux>MOLE</klux> \: of \: solute(nacl)}{volume \: of \: solution \: in \: liters}$ So, $= > \frac{1}{2} = \frac{mole \: of \: nacl}{ \frac{250}{1000} } \\ \\ = > \frac{1}{2} = \frac{mole \: of \: nacl}{ \frac{1}{4} } \\ \\ = > mole \: of \: nacl = \frac{1}{2 \times 4} = \frac{1}{8} mol$ So, Mole of NaCl = 1/8 mol As we know; $no. \: of \: mole \: = \frac{given \: weight}{molecular \: weight}$ So, $= > \frac{1}{8} = \frac{given \: weight}{58.5} \\ \\ = > given \: weight = \frac{58.5}{8} = 7.3125gm$ Therefore there are 1/8 mole and 7.3125 gm of NaCl present in 250 ml of 0.50M solution. Hope this HELPS...:)

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