How many molecules of oxygen are present in 8g of oxygen gas?

1.	How many molecules of oxygen are present in 8g of oxygen gas?
Answer» Explanation: hello mate here is your answer ______________ 1 mole of any substance = Avogadro number of molecules (6.023×10^23) 1 mole of oxygen = MOLECULAR weight = 2 × ATOMIC weight (as oxygen is DIATOMIC) 1 mole of oxygen = 2×16=32 gramme So, If 32 g = avagadro number of molecules 8 g = avagadro number ×8/32 No. Of molecules = avagadro number /4. number of molecules = given mass/molecular mass x avagadro’s constant (molecular mass of oxygen = 16) =8/16 x 6.022 x 10^23 =6.022 x 10^23/2 = 3.011 x 10^23 hope it helps you mate plz mark as BRAINLIEST

Answer»

Explanation:

hello mate

here is your answer

______________

1 mole of any substance = Avogadro number of molecules (6.023×10^23)

1 mole of oxygen = MOLECULAR weight = 2 × ATOMIC weight (as oxygen is DIATOMIC)

1 mole of oxygen = 2×16=32 gramme

So,

If 32 g = avagadro number of molecules

8 g = avagadro number ×8/32

No. Of molecules = avagadro number /4.

number of molecules = given mass/molecular mass x avagadro’s constant

(molecular mass of oxygen = 16)

=8/16 x 6.022 x 10^23

=6.022 x 10^23/2

= 3.011 x 10^23

hope it helps you mate

plz mark as BRAINLIEST

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