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How many (i) straight line (ii) traingle can be formed by 13 points, 6 of which are in straight line... |
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Answer» ∵ Straight line can be formed by joining two points & triangle can be formed by joining three non-collinear points. (i) Number of ways in which 2 points are selected from 13 points = \(^{13}C_2\). But given that 6 points are collinear (in straight line). Therefore these 6 points can form only one line. So, we have to subtract (\(^6C_2\) - 1) from the ways of selection 2 points from 13 points. ∴ Total straight lines that can be possible = \(^{13}C_2\) - (\(^6C_2\) - 1) = \(\frac{13\times 12}{2}\) - \(\frac{6\times 5}{2}\) + 1 = 13 x 6 - 15 + 1 = 78 - 14 = 64. (ii) Number of ways in which 3 non-collinear points are selected from 13 points = \(^{13}C_3\). But given that 6 points are collinear that never be formed any triangle. So, we have to subtract the selection of 3 non-collinear points from these 6 points. So, total number of triangle = \(^{13}C_3\) - \(^{6}C_3\) = \(\frac{13\times 12\times 11}{3\times 2}\) - \(\frac{6\times 5\times 4}{3\times 2}\) = 286 - 20 = 266. |
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