How many hours does it take to reduce 3 mol of `Fe^(3+)` to `Fe^(2+)` with 2.00 A current (1 Faraday=96,500 C `mol^(-1),R=8.314JK^(-1)mol^(-1)`).

How many hours does it take to reduce 3 mol of `Fe^(3+)` to `Fe^(2+)`

1.	How many hours does it take to reduce 3 mol of `Fe^(3+)` to `Fe^(2+)` with 2.00 A current (1 Faraday=96,500 C `mol^(-1),R=8.314JK^(-1)mol^(-1)`).
Answer» Correct Answer - 40.2 hrs `Fe^(3+)+e^(-)toFe^(2+)` i.e., 1 mol requires 1F. `therefore3` moles will require=3F=`3xx96500C` `t=Q//I=(3xx96500)//2.0=144750s=40.2`hrs.

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How many hours does it take to reduce 3 mol of `Fe^(3+)` to `Fe^(2+)` with 2.00 A current (1 Faraday=96,500 C `mol^(-1),R=8.314JK^(-1)mol^(-1)`).

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