How many grams of urea should be dissolved in 500 gram water so that the depression in freezing point is 0.2 K? Kf for solvent is 3.2 K kg mole⁻¹.Solve the example.

How many grams of urea should be dissolved in 500 gram water so that t

1.	How many grams of urea should be dissolved in 500 gram water so that the depression in freezing point is 0.2 K? Kf for solvent is 3.2 K kg mole⁻¹.Solve the example.
Answer» 1.875 gm.Explanation:Quantity of water = 500gm (Given)Freezing point = 0.2K (Given)Kf solvent = 3.2 (Given)DEPRESSION in Freezing point - ΔT = i × kf × m where m is the molarity of the solvent , Kf is the cryoscopic constant and t is the temperature. THEREFORE, 0.2 = 3.2 × x/ 60 × 0.5x = 30 × 2/32x = 30/16x = 1.875Thus, the amount of uread required is 1.875 gm.