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How many grams of neon will have the same number of atoms as 4gram of calcium |
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Answer» Mass of 1 ATOM of Ne = Molar mass/Avagadro No = 20 / 6.022*10²³ g Molar mass of Ca = 40 g Number of particles in 4 g of Ca = 4/40*6.022*10²³ = 6.022*10²² atoms Therefore, number of atoms of Ne same as 4 g of Ca = 20*6.022*10²²/6.022*10²³ =20/10 =2 g Ans: 2g of Ne has the same no of atoms as 4g of Ca. Hope you UNDERSTOOD it now! |
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