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How many grams of NaOH is required to neutralize 54.75 grams of HCL?many |
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Answer» Explanation:A Neutralization REACTION occurs when a strong acid reacts with a strong base to produce water and a salt (ionic compound). In our case, SULFURIC acid (strong acid) will react with sodium hydroxide (strong base) to form water and sodium sulfate: H 2 S O 4 + 2 N a O H → N a 2 S O 4 + 2 H 2 O We start with the units that we WANT to end up with and we set that equal to our given value, which will be multiplied by a conversion factor (the molar ratio from the balanced chemical EQUATION). The 98.08 g m o l represents the molar mass of sulfuric acid and the 40.0 g m o l is the molar mass of sodium hydroxide. So, what we have is: g N a O H = 25.0 g H 2 S O 4 × 1 m o l H 2 S O 4 98.08 g H 2 S O 4 × 2 m o l N a O H 1 m o l H 2 S O 4 × 40.0 g N a O H 1 m o l N a O H = |
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