1.

How many gm of ice at `-20^(@)C` are needed to cool 200 gm of water from `25^(@)C` to `10^(@)C`?A. 20 gmB. 30 gmC. 40 gmD. 50 gm

Answer» Correct Answer - 2
200x 1(25-10)
`mxx1/2 (0-20)+mxx80+mxx1xx(10-0)`
3000=100 m
m=30 gm


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