How many four-digit numbers can be formed using the digits 1, 2, 3, 5,

1.	How many four-digit numbers can be formed using the digits 1, 2, 3, 5, 8 if repetition ofdigits is not allowed ? How many of these are(i) divisible by(ii) divisible by 5(iii) odd(iv) between 2000 and 5000 ?
Answer» ANSWER: Therefore, there are 360 - 72 = 288(Option C) NUMBERS possible such that 2 and 5 don't COME together. There are 6 digits in total and we have to FORM a 4 digit number, hence that can be done in 6p4 ways.

How many four-digit numbers can be formed using the digits 1, 2, 3, 5, 8 if repetition ofdigits is not allowed ? How many of these are(i) divisible by(ii) divisible by 5(iii) odd(iv) between 2000 and 5000 ?

Answer»

Therefore, there are 360 - 72 = 288(Option C) NUMBERS possible such that 2 and 5 don't COME together. There are 6 digits in total and we have to FORM a 4 digit number, hence that can be done in 6p4 ways.

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How many four-digit numbers can be formed using the digits 1, 2, 3, 5, 8 if repetition ofdigits is not allowed ? How many of these are(i) divisible by(ii) divisible by 5(iii) odd(iv) between 2000 and 5000 ?​

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How many four-digit numbers can be formed using the digits 1, 2, 3, 5, 8 if repetition ofdigits is not allowed ? How many of these are(i) divisible by(ii) divisible by 5(iii) odd(iv) between 2000 and 5000 ?