1.

How many fluorine are there in 1.96 ions of aluminum fluoride​

Answer»

ANSWER:

molecules MASS of ALCL3 is (27*1)+(35.5*3)=133.5 amu

ALCL3 mass of aluminum =27mass of CHLORINE =106.5 so in 150 amu

ALCL3 mass of aluminum =30.33 mass



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