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How many even numbers greater than 3000 can be formed using digits 1,2,3,4,5,6 without repetition d

Answer»

Answer:

A B C D E F

the no. of permutations to get A PLACE =3!.......a

the no. of permutations to get B place = 5!.......b

the no. of permutations of getting C place = 4! ....c

the no. of permutations of getting D place=3!......d

the no of permutations of getting E place = 2!.....e

the no. of permutations of getting F place = 1!....F

according to law of permutation

multiple a, b,c,d,e,f

=3!*5!*4!*3!*2!*1! (5!=5*4*3*2*1= 120)

= 207360

hope this will help uui


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