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How many electrons would have to be removed when it is charged with 1.0 x 10-6 C? |
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Answer» Explanation:The CHARGE on an electron is 1.6×10−19C. So for PART (a) we can determine that the number of electrons WOULD be:1.0×10−71.6×10−19=6.25×1011 electronsFor part B, we need to know how may electrons are in the penny. The relative ATOMIC mass of copper is 63.546. By definition, 63.546g of copper would contain a number of atoms equal to Avogadro's constant which is 6.02×1023mol−1.So in 3.11g there would be the following number of atoms:3.1163.546×(6.02×1023)=2.95×1022 atomsThe atomic number of copper is 29, so a neutral copper atom has 29 electrons.Hence the fraction of electrons that would need to be removed would be:6.25×101129×(2.95×1022)=7.31×10−13 |
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